Pressure of solids

Pressure of a solid

Note. Convert the area to $\text{m}^2$. For example, a brick weighing $20\ \text{N}$ lies on a face of $200\ \text{cm}^2 = 0.02\ \text{m}^2$: $p = \dfrac{20}{0.02} = 1000\ \text{Pa}$. A person weighing $600\ \text{N}$ in boots with soles of $300\ \text{cm}^2$ presses on the snow with $p = \dfrac{600}{0.03} = 20\ \text{kPa}$, and on skis of $2000\ \text{cm}^2 = 0.2\ \text{m}^2$ with $p = \dfrac{600}{0.2} = 3\ \text{kPa}$.